x^4-3/5x^2-2/5=0

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Solution for x^4-3/5x^2-2/5=0 equation: 


x in (-oo:+oo)

x^4-((3/5)*x^2)-(2/5) = 0

x^4+(-3/5)*x^2-2/5 = 0

x^4-3/5*x^2-2/5 = 0

t_1 = x^2

1*t_1^2-3/5*t_1^1-2/5 = 0

t_1^2-3/5*t_1-2/5 = 0

DELTA = (-3/5)^2-(-2/5*1*4)

DELTA = 49/25

DELTA > 0

t_1 = ((49/25)^(1/2)+3/5)/(1*2) or t_1 = (3/5-(49/25)^(1/2))/(1*2)

t_1 = 1 or t_1 = -2/5

t_1 = -2/5

x^2+2/5 = 0

1*x^2 = -2/5 // : 1

x^2 = -2/5

t_1 = 1

x^2-1 = 0

1*x^2 = 1 // : 1

x^2 = 1

x^2 = 1 // ^ 1/2

abs(x) = 1

x = 1 or x = -1

x in { 1, -1 }

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